From eamon.nerbonne on February 03, 2011 10:02:14
Calling Fizz, with Fizz as:
bool Fizz(Func<int, bool> a) { return a(42); }
bool Fizz(Func<string, bool> a) { return a("42"); }
then Fizz(x => x=="a") is ok and valid and x inferred to be of type string and the second overload picked, but Fizz(x => true) cannot infer x; one must write Fizz( (string x) => true) since x can't be inferred - unless there's only one overload, in which case, it can be inferred.
None of this is implemented; ExpressionToCode simply assumes the type of x can always be inferred. ExpressionToCode should attempt to verify whether x's type can be inferred and if not, add types to all parameters of the lambda.
Original issue: http://code.google.com/p/expressiontocode/issues/detail?id=14
From eamon.nerbonne on February 03, 2011 10:02:14
Calling Fizz, with Fizz as:
then Fizz(x => x=="a") is ok and valid and x inferred to be of type string and the second overload picked, but Fizz(x => true) cannot infer x; one must write Fizz( (string x) => true) since x can't be inferred - unless there's only one overload, in which case, it can be inferred.
None of this is implemented; ExpressionToCode simply assumes the type of x can always be inferred. ExpressionToCode should attempt to verify whether x's type can be inferred and if not, add types to all parameters of the lambda.
Original issue: http://code.google.com/p/expressiontocode/issues/detail?id=14