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x^2 over a three-quarter power of a quadratic binomial beside another is integrated where that is elementary - #1728

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x-squared-over-a-three-quarter-power-beside-another-quadratic
Oct 4, 2026
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Rafael-SOWNet merged 2 commits into
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x-squared-over-a-three-quarter-power-beside-another-quadratic

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Part of #718.

x^2/((A + B x^2)^(3/4) (C + D x^2)) at B C - 2 A D = 0, Rubi's 1.1.2.4, is the difference of the two functions whose sum answers 1/((A + B x^2)^(1/4) (C + D x^2)) at that ratio, with another constant, and was declined; 2.5.0 declined it too:

integrand master 959c2d2e this
x^2/((a + b x^2)^(3/4) (2 a + b x^2)), a and b positive declined 0.7 s
the same, b negative declined 0.8 s
the same, a negative declined 0.7 s
x^2/((-2 + 3 x^2) (-1 + 3 x^2)^(3/4)) declined 0.2 s
x^2/((2 - 3 x^2)^(3/4) (4 - 3 x^2)) declined 0.2 s

What changes. The rule that answers 1/((A + B x^2)^(1/4) (C + D x^2)) at B C = 2 A D reads x^2 above the bar and (A + B x^2)^(3/4) below it as well, and answers it by the signs of A and B: an arctangent less an inverse hyperbolic tangent, over A^(1/4) and the cube of the root of B or -B -- of -A where A is negative, where the two share one argument -- times B/D, as the quarter power's answer is. The constants are solved for from the two functions' derivatives, and each form is checked at points in its sign case.

Tests: EllipticLookingQuotientOfBinomialsTest.XSquaredOverTheThreeQuarterPower, six rows across the sign cases of A and B, each differentiated back at points in its case, the negative side among them; all six fail on master.

Measured first on the 446 problems of Rubi's 1.1.2.3 and 1.1.2.4 with a quarter power in them or in their answers, 196 run, at the corpus's 5-second budget, against master 8f3757cd, the branch's base:

master this
solved 142 160
wrong 0 0

Measured then on the Rubi corpus against master 8f3757cd:

master this
family 0, independent suites (1814) 1766 1766
family 1, 40 a file (1381) 1296 1298
families 2 to 8, sampled (2410) 2215 2218

No answer is wrong in the sample on either build. Of the 25 problems the two builds disagreed on, run again one build at a time, 20 are answered here and not on master, 18 of them 1.1.2.4's of this shape, and four are answered on both. One went the other way in that run, 1/((a g + b g x)^3 (A + B ln(e (a + b x)/(c + d x)))), which has no quarter power in it and takes 35 to 43 s on either build without a budget, measured alternately, at the edge of the corpus's.

The suite passes on the commit measured, c1fe3336, 14,597 tests, and so does the allocation gate. Master 959c2d2e is merged in since, without conflicts; the calculus tests pass on the merge, 4,010 of them.

🤖 Generated with Claude Code

https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura

Rafael-SOWNet and others added 2 commits October 3, 2026 18:18
… is integrated where that is elementary

x^2/((A + B x^2)^(3/4) (C + D x^2)) at B C - 2 A D = 0, Rubi's 1.1.2.4, is the difference of the
two functions whose sum answers the quarter power at that ratio, with another constant, and was
declined. It is answered by the signs of A and B now, the constants solved for from the two
functions' derivatives and each form checked at points in its sign case.

Part of #718.

Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
@Rafael-SOWNet Rafael-SOWNet added this to the 2.6.0 milestone Oct 4, 2026
@Rafael-SOWNet
Rafael-SOWNet merged commit 04e2fe6 into master Oct 4, 2026
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