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A trinomial the numerator holds is divided out of a power of it - #1845
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Rafael-SOWNet merged 3 commits intoOct 11, 2026
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Part of #718. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Part of #718.
The reduction of a polynomial over a power of a trinomial in
x^nnow first divides the trinomial out of the numerator, wherever it divides exactly. The trinomial arrives made monic, so its content in the symbols is taken out of it first.Rubi's 1.2.2.5:83 writes
(d + g x + f x^2)(a + b x^2 + c x^4)/(a + b x^2 + c x^4)^4multiplied out. Its answer, measured on the merged branch:On this branch the answer is the same as for
(d + g x + f x^2)/(a + b x^2 + c x^4)^3.Corpus, against master 3c86dda, before #1844 (a Rubi pocket of 14,158 problems, families 0–8 sampled): every family file agrees between the two arms. Two problems moved: 1.2.2.5:83 is solved, and 4.7.5:392 went from a timeout to unsolved. Neither arm gives a wrong answer. The allocation gate and the suite (15,196 passed) are green. Since then #1844 solves row 83 on master too, so what this PR adds there is the shorter, faster answer.
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https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura