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A power of x below the bar beside a root of a binomial is rationalised by dividing by the root - #1849
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Rafael-SOWNet merged 3 commits intoOct 11, 2026
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…d by dividing by the root Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
…tial-beside-another-binomial
Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
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Part of #718.
SolveByDividingByTheRootrationalises(a + b x^n)^p/(c + d x^n)by dividing by the root, but it declined as soon as a power ofxstood below the bar beside the other binomial. It now takes that power ofxinto the lowered exponent, so(a + b x^3)^(1/3)/(x^2 (c + d x^3))(Rubi 1.1.3.4:763) is answered.Measured on a15d60e (master) and this branch:
(a+b x^3)^(1/3)/(x^2 (c+d x^3))(a+b x^3)^(1/3)/(x^11 (c+d x^3))(a+b x^3)^(4/3)/(x^2 (c+d x^3))(a+b x^3)^(4/3)/(x^14 (c+d x^3))1/(x^2 (a+b x^3)^(2/3) (c+d x^3))(a+b x^3)^(1/3)/(x^2 (a d-b d x^3))1/(x^2 (1-x^3)^(2/3) (1+x^3))Corpus, every family against 0608d5e: 17 problems move from unsolved to solved (1.1.3.4:666–669, 723–724, 763–766, 799–803, 838–839), 0 wrong, nothing lost. 1.1.3.4:857 and 3.2.1:292 time out on both arms when re-run alone. Kernel gate passed; suite 15,220 passed.
A
BREAKING-CHANGES.mdentry records the new answers, measured against 2.5.0, which declines all of them.🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura