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A sine's binomial cube below the bar is split over the cube's two factors - #1850
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…tors With a and b symbols, a + b sin^3 has no rational factor, so the split over a symbolic quadratic in the sine declined. It is written b (s + r)(s^2 - r s + r^2) with r = (a/b)^(1/3), which that split answers (Rubi 4.1.7). Part of #718. Co-Authored-By: Claude Opus 5.5 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura
…the-sine-over-its-root
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Part of #718.
With
aandbsymbols,a + b sin(c + d x)^3has no rational factor, so the split over a symbolic quadratic in the sine declined. The cube is now writtenb (s + r)(s^2 - r s + r^2)withr = (a/b)^(1/3), which that split answers. The route is tried only after the existing one declines.Measured on a41415b (master) and this branch:
csc(c+d x)/(a+b sin(c+d x)^3)csc(c+d x)^2/(...)csc(c+d x)^3/(...)csc(c+d x)^4/(...)csc(c+d x)^5/(...)sec(c+d x)^2/(...)sec(c+d x)^4/(...)Corpus, every family against a15d60e: 7 problems move from unsolved to solved (4.1.7:239–241, 246–247, 496–497), 0 wrong, nothing lost. 1.1.3.4:857 times out on both arms. Kernel gate passed; suite 15,223 passed.
A
BREAKING-CHANGES.mdentry records the new answers; 2.5.0 declines all of them.🤖 Generated with Claude Code
https://claude.ai/code/session_012sonx8iAspMiwRwokT1Ura