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Construct Binary Tree from Inorder and Postorder Traversal (InOrderPostOrderBinaryTree.java)
E.g., INCORRECT - The solution doesn't solve the postorder problem; it solves the preorder+inorder problem instead.
INCORRECT - The solution doesn't solve the postorder problem; it solves the preorder+inorder problem instead.
VERDICT: NEEDS_IMPROVEMENT
Sum Root to Leaf Numbers (SumRootToLeaf)
Great work! Your solution is correct, efficient, and well-structured. Here are some minor suggestions:
Space Complexity: Your analysis states O(n), but the actual space complexity is O(h), where h is the height of the tree. This is because the recursion stack depth depends on the height of the tree, not the total number of nodes. In the worst case (a completely skewed tree), h = n, so O(n) is technically correct as an upper bound, but O(h) is more precise and informative.
Field Initialization: While Java automatically initializes instance int fields to 0, it's a best practice to explicitly initialize them, especially for fields that are modified by methods. Consider initializing result to 0 in the constructor or at declaration:
intresult = 0;
Code Style: Your code is clean and well-commented. The approach comment at the top is a nice touch. Keep up the good work!
Edge Cases: Consider what happens if the root is null. Your current solution would return 0 (since result is 0 and the helper returns immediately), which is correct behavior. However, you might want to add a null check at the beginning of sumNumbers for clarity:
if (root == null) return0;
VERDICT: PASS
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